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Con
September 13th, 2009, 10:42 PM
http://img7.imageshack.us/img7/7656/wtfmh.png
the fuck is this
what rule do I use

Mass
September 13th, 2009, 10:44 PM
uh

something with logarithms and trigonometric functions


no idea

flibitijibibo
September 13th, 2009, 10:44 PM
Wait, I don't know what I'm thinking. Lemme write it out one more time.

∫ (e^sin(x)cos(x))dx

u = sin(x)
du = cos(x)dx

∫ (e^u) du

e^u

e^sin(x)

Aw, it didn't show later posts. Fuck.

Phopojijo
September 13th, 2009, 10:53 PM
You forgot about the second term that a product rule creates so that's wrong...

Timo
September 13th, 2009, 10:54 PM
Integration by substitution, use u = sin x.
du = cosx dx, so all you need to integrate is e^u

Con
September 13th, 2009, 11:08 PM
Integration by substitution, use u = sin x.
du = cosx dx, so all you need to integrate is e^u
I'd forgotten all about that. Seems so easy now, thanks!

TheGhost
September 13th, 2009, 11:15 PM
Integration by substitution, use u = sin x.
du = cosx dx, so all you need to integrate is e^u du

ftfy, but yeah

winrar

Heathen
September 14th, 2009, 12:43 AM
winrar?

Rook
September 14th, 2009, 02:46 AM
winrar?

winrar (http://www.rarlab.com/)

p0lar_bear
September 14th, 2009, 12:56 PM
Like I said on AIM:

math s(x))dx

Syuusuke
September 14th, 2009, 02:47 PM
at least math proves sex is fun.